Base | Representation |
---|---|
bin | 1110111010010001101… |
… | …0100110000101110101 |
3 | 220111012100001202220100 |
4 | 3232210122212011311 |
5 | 13144104321140103 |
6 | 313402354024313 |
7 | 24335630605044 |
oct | 3564432460565 |
9 | 814170052810 |
10 | 256161505653 |
11 | 99701545689 |
12 | 4178bb78099 |
13 | 1b204754821 |
14 | c580c6255b |
15 | 69e3c055a3 |
hex | 3ba46a6175 |
256161505653 has 12 divisors (see below), whose sum is σ = 371870418400. Its totient is φ = 169916173416.
The previous prime is 256161505619. The next prime is 256161505681. The reversal of 256161505653 is 356505161652.
256161505653 is a `hidden beast` number, since 25 + 6 + 1 + 61 + 5 + 0 + 565 + 3 = 666.
It is a de Polignac number, because none of the positive numbers 2k-256161505653 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 256161505599 and 256161505608.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (256161505693) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 71511751 + ... + 71515332.
Almost surely, 2256161505653 is an apocalyptic number.
It is an amenable number.
256161505653 is a deficient number, since it is larger than the sum of its proper divisors (115708912747).
256161505653 is a wasteful number, since it uses less digits than its factorization.
256161505653 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143027288 (or 143027285 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 45.
The spelling of 256161505653 in words is "two hundred fifty-six billion, one hundred sixty-one million, five hundred five thousand, six hundred fifty-three".
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