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255089503 is a prime number
BaseRepresentation
bin11110011010001…
…01101101011111
3122202222220000101
433031011231133
51010300331003
641151241531
76215140114
oct1715055537
9582886011
10255089503
11120a9a579
12715192a7
1340b05146
1425c4290b
15175dc11d
hexf345b5f

255089503 has 2 divisors, whose sum is σ = 255089504. Its totient is φ = 255089502.

The previous prime is 255089467. The next prime is 255089519. The reversal of 255089503 is 305980552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255089503 - 29 = 255088991 is a prime.

It is a super-4 number, since 4×2550895034 (a number of 35 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255089563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127544751 + 127544752.

It is an arithmetic number, because the mean of its divisors is an integer number (127544752).

Almost surely, 2255089503 is an apocalyptic number.

255089503 is a deficient number, since it is larger than the sum of its proper divisors (1).

255089503 is an equidigital number, since it uses as much as digits as its factorization.

255089503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 37.

The square root of 255089503 is about 15971.5216244414. The cubic root of 255089503 is about 634.2067537128.

The spelling of 255089503 in words is "two hundred fifty-five million, eighty-nine thousand, five hundred three".