253401330055 has 4 divisors (see below), whose sum is σ = 304081596072. Its totient is φ = 202721064040.

The previous prime is 253401330019. The next prime is 253401330097. The reversal of 253401330055 is 550033104352.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 253401330055 - 2¹⁵ = 253401297287 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 253401329999 and 253401330026.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25340133001 + ... + 25340133010.

It is an arithmetic number, because the mean of its divisors is an integer number (76020399018).

Almost surely, 2^253401330055 is an apocalyptic number.

253401330055 is a deficient number, since it is larger than the sum of its proper divisors (50680266017).

253401330055 is an equidigital number, since it uses as much as digits as its factorization.

253401330055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50680266016.

The product of its (nonzero) digits is 27000, while the sum is 31.

The spelling of 253401330055 in words is "two hundred fifty-three billion, four hundred one million, three hundred thirty thousand, fifty-five".