Base | Representation |
---|---|
bin | 1110101101001010001… |
… | …1110001100011111011 |
3 | 220011002222001010210222 |
4 | 3223102203301203323 |
5 | 13114402004242241 |
6 | 312021142530255 |
7 | 24152446326404 |
oct | 3532243614373 |
9 | 804088033728 |
10 | 252640696571 |
11 | 981650a570a |
12 | 40b68a3698b |
13 | 1aa931b0743 |
14 | c3294089ab |
15 | 6889a87a4b |
hex | 3ad28f18fb |
252640696571 has 2 divisors, whose sum is σ = 252640696572. Its totient is φ = 252640696570.
The previous prime is 252640696547. The next prime is 252640696577. The reversal of 252640696571 is 175696046252.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 252640696571 - 218 = 252640434427 is a prime.
It is a super-3 number, since 3×2526406965713 (a number of 35 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (252640696577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126320348285 + 126320348286.
It is an arithmetic number, because the mean of its divisors is an integer number (126320348286).
Almost surely, 2252640696571 is an apocalyptic number.
252640696571 is a deficient number, since it is larger than the sum of its proper divisors (1).
252640696571 is an equidigital number, since it uses as much as digits as its factorization.
252640696571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5443200, while the sum is 53.
The spelling of 252640696571 in words is "two hundred fifty-two billion, six hundred forty million, six hundred ninety-six thousand, five hundred seventy-one".
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