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2523125573 is a prime number
BaseRepresentation
bin1001011001100011…
…1101011101000101
320111211201001121022
42112120331131011
520131410004243
61054211200525
7116345133143
oct22630753505
96454631538
102523125573
111085269651
125a4ba6145
13312968417
1419d150593
15eb797b68
hex9663d745

2523125573 has 2 divisors, whose sum is σ = 2523125574. Its totient is φ = 2523125572.

The previous prime is 2523125537. The next prime is 2523125587. The reversal of 2523125573 is 3755213252.

Together with previous prime (2523125537) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1409101444 + 1114024129 = 37538^2 + 33377^2 .

It is a cyclic number.

It is not a de Polignac number, because 2523125573 - 28 = 2523125317 is a prime.

It is a super-4 number, since 4×25231255734 (a number of 39 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2523125173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1261562786 + 1261562787.

It is an arithmetic number, because the mean of its divisors is an integer number (1261562787).

Almost surely, 22523125573 is an apocalyptic number.

It is an amenable number.

2523125573 is a deficient number, since it is larger than the sum of its proper divisors (1).

2523125573 is an equidigital number, since it uses as much as digits as its factorization.

2523125573 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 63000, while the sum is 35.

The square root of 2523125573 is about 50230.7233971401. The cubic root of 2523125573 is about 1361.3808015043.

The spelling of 2523125573 in words is "two billion, five hundred twenty-three million, one hundred twenty-five thousand, five hundred seventy-three".