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2414012021343 = 321361338239039
BaseRepresentation
bin100011001000001110010…
…101000011101001011111
322112202222122111122201100
4203020032111003221133
5304022344034140333
65044552023244143
7336256316423166
oct43101625035137
98482878448640
102414012021343
1185085a94220a
1232ba278a9653
13146842b301b0
1484ba59783dd
1542bd9ad1213
hex2320e543a5f

2414012021343 has 24 divisors (see below), whose sum is σ = 3816689327360. Its totient is φ = 1461192644160.

The previous prime is 2414012021341. The next prime is 2414012021383. The reversal of 2414012021343 is 3431202104142.

2414012021343 is a `hidden beast` number, since 2 + 4 + 1 + 401 + 2 + 0 + 213 + 43 = 666.

It is not a de Polignac number, because 2414012021343 - 21 = 2414012021341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2414012021341) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 169112383 + ... + 169126656.

Almost surely, 22414012021343 is an apocalyptic number.

2414012021343 is a deficient number, since it is larger than the sum of its proper divisors (1402677306017).

2414012021343 is a wasteful number, since it uses less digits than its factorization.

2414012021343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 338239119 (or 338239116 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 2414012021343 its reverse (3431202104142), we get a palindrome (5845214125485).

The spelling of 2414012021343 in words is "two trillion, four hundred fourteen billion, twelve million, twenty-one thousand, three hundred forty-three".

Divisors: 1 3 9 13 39 61 117 183 549 793 2379 7137 338239039 1014717117 3044151351 4397107507 13191322521 20632581379 39573967563 61897744137 185693232411 268223557927 804670673781 2414012021343