Base | Representation |
---|---|
bin | 100001101010100001101… |
… | …001111111100001101101 |
3 | 22012011022010210022202202 |
4 | 201222201221333201231 |
5 | 300400323030421013 |
6 | 4530432520031245 |
7 | 326065215120053 |
oct | 41524151774155 |
9 | 8164263708682 |
10 | 2313404545133 |
11 | 812122612260 |
12 | 31442a602525 |
13 | 13a1cb507c96 |
14 | 7dd7dd861d3 |
15 | 4029c39d858 |
hex | 21aa1a7f86d |
2313404545133 has 16 divisors (see below), whose sum is σ = 2606555059776. Its totient is φ = 2035148019840.
The previous prime is 2313404545103. The next prime is 2313404545159. The reversal of 2313404545133 is 3315454043132.
It is a cyclic number.
It is not a de Polignac number, because 2313404545133 - 210 = 2313404544109 is a prime.
It is a super-3 number, since 3×23134045451333 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2313404545103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27136235 + ... + 27221352.
It is an arithmetic number, because the mean of its divisors is an integer number (162909691236).
Almost surely, 22313404545133 is an apocalyptic number.
It is an amenable number.
2313404545133 is a deficient number, since it is larger than the sum of its proper divisors (293150514643).
2313404545133 is a wasteful number, since it uses less digits than its factorization.
2313404545133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54357724.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 2313404545133 its reverse (3315454043132), we get a palindrome (5628858588265).
The spelling of 2313404545133 in words is "two trillion, three hundred thirteen billion, four hundred four million, five hundred forty-five thousand, one hundred thirty-three".
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