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2301121019993 is a prime number
BaseRepresentation
bin100001011111000101100…
…000000100000001011001
322010222121002011121001012
4201133011200010001121
5300200143440114433
64521042001303305
7325151631641315
oct41370540040131
98128532147035
102301121019993
11807999909a94
12311b80934b35
13138cc16c3403
147d536842b45
153eccdcc5848
hex217c5804059

2301121019993 has 2 divisors, whose sum is σ = 2301121019994. Its totient is φ = 2301121019992.

The previous prime is 2301121019971. The next prime is 2301121020001. The reversal of 2301121019993 is 3999101211032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1692413661184 + 608707358809 = 1300928^2 + 780197^2 .

It is a cyclic number.

It is not a de Polignac number, because 2301121019993 - 224 = 2301104242777 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2301121019993.

It is not a weakly prime, because it can be changed into another prime (2301121019293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1150560509996 + 1150560509997.

It is an arithmetic number, because the mean of its divisors is an integer number (1150560509997).

Almost surely, 22301121019993 is an apocalyptic number.

It is an amenable number.

2301121019993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2301121019993 is an equidigital number, since it uses as much as digits as its factorization.

2301121019993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26244, while the sum is 41.

The spelling of 2301121019993 in words is "two trillion, three hundred one billion, one hundred twenty-one million, nineteen thousand, nine hundred ninety-three".