Base | Representation |
---|---|
bin | 100000000010001010001… |
… | …110111111001010110011 |
3 | 21210110001100011120002202 |
4 | 200002022032333022303 |
5 | 242031322131040430 |
6 | 4403141024133415 |
7 | 315020214002450 |
oct | 40021216771263 |
9 | 7713040146082 |
10 | 2201342440115 |
11 | 779647467125 |
12 | 2b677516726b |
13 | 12c77ca2a8c0 |
14 | 7878cd7c827 |
15 | 3c3de226d45 |
hex | 2008a3bf2b3 |
2201342440115 has 16 divisors (see below), whose sum is σ = 3251213450688. Its totient is φ = 1393377192576.
The previous prime is 2201342440097. The next prime is 2201342440123. The reversal of 2201342440115 is 5110442431022.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 2201342440115 - 228 = 2201074004659 is a prime.
It is a super-2 number, since 2×22013424401152 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2419057172 + ... + 2419058081.
It is an arithmetic number, because the mean of its divisors is an integer number (203200840668).
Almost surely, 22201342440115 is an apocalyptic number.
2201342440115 is a deficient number, since it is larger than the sum of its proper divisors (1049871010573).
2201342440115 is a wasteful number, since it uses less digits than its factorization.
2201342440115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4838115278.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 2201342440115 its reverse (5110442431022), we get a palindrome (7311784871137).
The spelling of 2201342440115 in words is "two trillion, two hundred one billion, three hundred forty-two million, four hundred forty thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •