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2201342440115 = 57134838115253
BaseRepresentation
bin100000000010001010001…
…110111111001010110011
321210110001100011120002202
4200002022032333022303
5242031322131040430
64403141024133415
7315020214002450
oct40021216771263
97713040146082
102201342440115
11779647467125
122b677516726b
1312c77ca2a8c0
147878cd7c827
153c3de226d45
hex2008a3bf2b3

2201342440115 has 16 divisors (see below), whose sum is σ = 3251213450688. Its totient is φ = 1393377192576.

The previous prime is 2201342440097. The next prime is 2201342440123. The reversal of 2201342440115 is 5110442431022.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 2201342440115 - 228 = 2201074004659 is a prime.

It is a super-2 number, since 2×22013424401152 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2419057172 + ... + 2419058081.

It is an arithmetic number, because the mean of its divisors is an integer number (203200840668).

Almost surely, 22201342440115 is an apocalyptic number.

2201342440115 is a deficient number, since it is larger than the sum of its proper divisors (1049871010573).

2201342440115 is a wasteful number, since it uses less digits than its factorization.

2201342440115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4838115278.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 2201342440115 its reverse (5110442431022), we get a palindrome (7311784871137).

The spelling of 2201342440115 in words is "two trillion, two hundred one billion, three hundred forty-two million, four hundred forty thousand, one hundred fifteen".

Divisors: 1 5 7 13 35 65 91 455 4838115253 24190576265 33866806771 62895498289 169334033855 314477491445 440268488023 2201342440115