Base | Representation |
---|---|
bin | 1001101111100011101001… |
… | …01010000010110101001011 |
3 | 2210212020022210102000121021 |
4 | 10313301310222002311023 |
5 | 10302012410014114042 |
6 | 113322343102453311 |
7 | 4340631524410132 |
oct | 467616452026513 |
9 | 83766283360537 |
10 | 21425254051147 |
11 | 69104433a1781 |
12 | 24a0436294237 |
13 | bc5514c5472b |
14 | 540db8862919 |
15 | 2724c014c867 |
hex | 137c74a82d4b |
21425254051147 has 2 divisors, whose sum is σ = 21425254051148. Its totient is φ = 21425254051146.
The previous prime is 21425254051133. The next prime is 21425254051151. The reversal of 21425254051147 is 74115045252412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21425254051147 - 215 = 21425254018379 is a prime.
It is a super-2 number, since 2×214252540511472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21425254051177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10712627025573 + 10712627025574.
It is an arithmetic number, because the mean of its divisors is an integer number (10712627025574).
Almost surely, 221425254051147 is an apocalyptic number.
21425254051147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21425254051147 is an equidigital number, since it uses as much as digits as its factorization.
21425254051147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448000, while the sum is 43.
The spelling of 21425254051147 in words is "twenty-one trillion, four hundred twenty-five billion, two hundred fifty-four million, fifty-one thousand, one hundred forty-seven".
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