Base | Representation |
---|---|
bin | 1100011101010011010… |
… | …1111011011001010101 |
3 | 202110102201111011011222 |
4 | 3013110311323121111 |
5 | 12001310210213323 |
6 | 242153231340125 |
7 | 21314502366206 |
oct | 3072465733125 |
9 | 673381434158 |
10 | 214024304213 |
11 | 8284915a565 |
12 | 35590381645 |
13 | 1724a98a635 |
14 | a5048c35ad |
15 | 58797a89c8 |
hex | 31d4d7b655 |
214024304213 has 4 divisors (see below), whose sum is σ = 223329708768. Its totient is φ = 204718899660.
The previous prime is 214024304177. The next prime is 214024304239. The reversal of 214024304213 is 312403420412.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 214024304213 - 212 = 214024300117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (214024304293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4652702243 + ... + 4652702288.
It is an arithmetic number, because the mean of its divisors is an integer number (55832427192).
Almost surely, 2214024304213 is an apocalyptic number.
214024304213 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
214024304213 is a deficient number, since it is larger than the sum of its proper divisors (9305404555).
214024304213 is an equidigital number, since it uses as much as digits as its factorization.
214024304213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9305404554.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 214024304213 its reverse (312403420412), we get a palindrome (526427724625).
The spelling of 214024304213 in words is "two hundred fourteen billion, twenty-four million, three hundred four thousand, two hundred thirteen".
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