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213312013333 is a prime number
BaseRepresentation
bin1100011010101001100…
…0110000010000010101
3202101121002012000210021
43012222120300100111
511443330333411313
6241554424425141
721261033124336
oct3065230602025
9671532160707
10213312013333
1182513085911
12354119181b1
1317166236a43
14a47806a28d
155836ea978d
hex31aa630415

213312013333 has 2 divisors, whose sum is σ = 213312013334. Its totient is φ = 213312013332.

The previous prime is 213312013319. The next prime is 213312013351. The reversal of 213312013333 is 333310213312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 182552816644 + 30759196689 = 427262^2 + 175383^2 .

It is a cyclic number.

It is not a de Polignac number, because 213312013333 - 217 = 213311882261 is a prime.

It is a super-4 number, since 4×2133120133334 (a number of 46 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213312013298 and 213312013307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213312013373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106656006666 + 106656006667.

It is an arithmetic number, because the mean of its divisors is an integer number (106656006667).

Almost surely, 2213312013333 is an apocalyptic number.

It is an amenable number.

213312013333 is a deficient number, since it is larger than the sum of its proper divisors (1).

213312013333 is an equidigital number, since it uses as much as digits as its factorization.

213312013333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 213312013333 its reverse (333310213312), we get a palindrome (546622226645).

The spelling of 213312013333 in words is "two hundred thirteen billion, three hundred twelve million, thirteen thousand, three hundred thirty-three".