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2131302119981 is a prime number
BaseRepresentation
bin11111000000111011100…
…000010111101000101101
321112202021002221122101212
4133000323200113220231
5234404401320314411
64311035013044205
7306660440052416
oct37007340275055
97482232848355
102131302119981
11751975535a31
122a5088926665
13125c9a136aa8
1475226c6c80d
153a6902ee68b
hex1f03b817a2d

2131302119981 has 2 divisors, whose sum is σ = 2131302119982. Its totient is φ = 2131302119980.

The previous prime is 2131302119971. The next prime is 2131302119987. The reversal of 2131302119981 is 1899112031312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1686491822500 + 444810297481 = 1298650^2 + 666941^2 .

It is a cyclic number.

It is not a de Polignac number, because 2131302119981 - 214 = 2131302103597 is a prime.

It is a super-2 number, since 2×21313021199812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131302119987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065651059990 + 1065651059991.

It is an arithmetic number, because the mean of its divisors is an integer number (1065651059991).

Almost surely, 22131302119981 is an apocalyptic number.

It is an amenable number.

2131302119981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131302119981 is an equidigital number, since it uses as much as digits as its factorization.

2131302119981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 41.

The spelling of 2131302119981 in words is "two trillion, one hundred thirty-one billion, three hundred two million, one hundred nineteen thousand, nine hundred eighty-one".