Base | Representation |
---|---|
bin | 11111000000110001110… |
… | …110010100010001011011 |
3 | 21112201211211002020102200 |
4 | 133000301312110101123 |
5 | 234404033331214321 |
6 | 4311010544301243 |
7 | 306653431654452 |
oct | 37006166242133 |
9 | 7481754066380 |
10 | 2131140101211 |
11 | 7518a2034920 |
12 | 2a5042611823 |
13 | 125c726ba4b4 |
14 | 7520d535b99 |
15 | 3a680e98d26 |
hex | 1f031d9445b |
2131140101211 has 24 divisors (see below), whose sum is σ = 3363881137344. Its totient is φ = 1289399685360.
The previous prime is 2131140101201. The next prime is 2131140101261. The reversal of 2131140101211 is 1121010411312.
2131140101211 is a `hidden beast` number, since 2 + 1 + 311 + 40 + 101 + 211 = 666.
It is not a de Polignac number, because 2131140101211 - 217 = 2131139970139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2131140101201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18278061 + ... + 18394286.
It is an arithmetic number, because the mean of its divisors is an integer number (140161714056).
Almost surely, 22131140101211 is an apocalyptic number.
2131140101211 is a deficient number, since it is larger than the sum of its proper divisors (1232741036133).
2131140101211 is a wasteful number, since it uses less digits than its factorization.
2131140101211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36672951 (or 36672948 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 18.
Adding to 2131140101211 its reverse (1121010411312), we get a palindrome (3252150512523).
The spelling of 2131140101211 in words is "two trillion, one hundred thirty-one billion, one hundred forty million, one hundred one thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •