Base | Representation |
---|---|
bin | 1100011001111010010… |
… | …1011011100111111111 |
3 | 202101002021121102102121 |
4 | 3012132211123213333 |
5 | 11442424141310421 |
6 | 241523032503411 |
7 | 21253110124432 |
oct | 3063645334777 |
9 | 671067542377 |
10 | 213114010111 |
11 | 82421337092 |
12 | 3537754ab67 |
13 | 171341cb582 |
14 | a459a47819 |
15 | 58248e6d41 |
hex | 319e95b9ff |
213114010111 has 2 divisors, whose sum is σ = 213114010112. Its totient is φ = 213114010110.
The previous prime is 213114010103. The next prime is 213114010133. The reversal of 213114010111 is 111010411312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213114010111 - 23 = 213114010103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213114011111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106557005055 + 106557005056.
It is an arithmetic number, because the mean of its divisors is an integer number (106557005056).
Almost surely, 2213114010111 is an apocalyptic number.
213114010111 is a deficient number, since it is larger than the sum of its proper divisors (1).
213114010111 is an equidigital number, since it uses as much as digits as its factorization.
213114010111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 213114010111 its reverse (111010411312), we get a palindrome (324124421423).
The spelling of 213114010111 in words is "two hundred thirteen billion, one hundred fourteen million, ten thousand, one hundred eleven".
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