Base | Representation |
---|---|
bin | 1100010110010000101… |
… | …1011111110100001000 |
3 | 202021112222210111201202 |
4 | 3011210023133310020 |
5 | 11433422314224000 |
6 | 241241510403332 |
7 | 21216611244026 |
oct | 3054413376410 |
9 | 667488714652 |
10 | 212134133000 |
11 | 81a69207999 |
12 | 35143360548 |
13 | 170091b872a |
14 | a3a5857716 |
15 | 57b888cdd5 |
hex | 31642dfd08 |
212134133000 has 32 divisors (see below), whose sum is σ = 496393873560. Its totient is φ = 84853652800.
The previous prime is 212134132993. The next prime is 212134133009. The reversal of 212134133000 is 331431212.
It can be written as a sum of positive squares in 4 ways, for example, as 18247146724 + 193886986276 = 135082^2 + 440326^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (212134133009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 106066067 + ... + 106068066.
Almost surely, 2212134133000 is an apocalyptic number.
212134133000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
212134133000 is an abundant number, since it is smaller than the sum of its proper divisors (284259740560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
212134133000 is a wasteful number, since it uses less digits than its factorization.
212134133000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212134154 (or 212134140 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 212134133000 its reverse (331431212), we get a palindrome (212465564212).
The spelling of 212134133000 in words is "two hundred twelve billion, one hundred thirty-four million, one hundred thirty-three thousand".
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