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212112203113 = 1311619177123
BaseRepresentation
bin1100010110001011011…
…1110101110101101001
3202021111110112100120201
43011202313311311221
511433401210444423
6241235404352201
721216223656346
oct3054267656551
9667443470521
10212112203113
1181a57899718
1235137b45661
13170047aaa75
14a3a29897cd
1557b69aa2ad
hex3162df5d69

212112203113 has 4 divisors (see below), whose sum is σ = 213731380368. Its totient is φ = 210493025860.

The previous prime is 212112203101. The next prime is 212112203131. The reversal of 212112203113 is 311302211212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 212112203113 - 217 = 212112072041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (212112203183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809588431 + ... + 809588692.

It is an arithmetic number, because the mean of its divisors is an integer number (53432845092).

Almost surely, 2212112203113 is an apocalyptic number.

It is an amenable number.

212112203113 is a deficient number, since it is larger than the sum of its proper divisors (1619177255).

212112203113 is a wasteful number, since it uses less digits than its factorization.

212112203113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1619177254.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 212112203113 its reverse (311302211212), we get a palindrome (523414414325).

The spelling of 212112203113 in words is "two hundred twelve billion, one hundred twelve million, two hundred three thousand, one hundred thirteen".

Divisors: 1 131 1619177123 212112203113