Base | Representation |
---|---|
bin | 10011101010111110… |
… | …011011000000110100 |
3 | 2000112000221220212011 |
4 | 103222332123000310 |
5 | 321224224220200 |
6 | 13411531534004 |
7 | 1345265620156 |
oct | 235276330064 |
9 | 60460856764 |
10 | 21122101300 |
11 | 8a5996a373 |
12 | 41158ba304 |
13 | 1cb7cc62c1 |
14 | 1045338ad6 |
15 | 83951a5ba |
hex | 4eaf9b034 |
21122101300 has 18 divisors (see below), whose sum is σ = 45834960038. Its totient is φ = 8448840480.
The previous prime is 21122101291. The next prime is 21122101307. The reversal of 21122101300 is 310122112.
It can be written as a sum of positive squares in 3 ways, for example, as 308845476 + 20813255824 = 17574^2 + 144268^2 .
It is a super-2 number, since 2×211221013002 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21122101307) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 105610407 + ... + 105610606.
Almost surely, 221122101300 is an apocalyptic number.
21122101300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21122101300 is an abundant number, since it is smaller than the sum of its proper divisors (24712858738).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21122101300 is a wasteful number, since it uses less digits than its factorization.
21122101300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211221027 (or 211221020 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 21122101300 its reverse (310122112), we get a palindrome (21432223412).
The spelling of 21122101300 in words is "twenty-one billion, one hundred twenty-two million, one hundred one thousand, three hundred".
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