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211210221110113 is a prime number
BaseRepresentation
bin110000000001100000110110…
…001100111100001101100001
31000200211111111110101121120001
4300001200312030330031201
5210140432013101010423
62025112345221020001
762326302113456041
oct6001406614741541
91020744443347501
10211210221110113
116133082a6397a5
121b831b57854601
1390b1066458344
143a228b4919721
1519640e11a4cad
hexc0183633c361

211210221110113 has 2 divisors, whose sum is σ = 211210221110114. Its totient is φ = 211210221110112.

The previous prime is 211210221110087. The next prime is 211210221110137. The reversal of 211210221110113 is 311011122012112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110103636608784 + 101106584501329 = 10493028^2 + 10055177^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211210221110113 is a prime.

It is not a weakly prime, because it can be changed into another prime (211210221110153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605110555056 + 105605110555057.

It is an arithmetic number, because the mean of its divisors is an integer number (105605110555057).

Almost surely, 2211210221110113 is an apocalyptic number.

It is an amenable number.

211210221110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211210221110113 is an equidigital number, since it uses as much as digits as its factorization.

211210221110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 211210221110113 its reverse (311011122012112), we get a palindrome (522221343122225).

The spelling of 211210221110113 in words is "two hundred eleven trillion, two hundred ten billion, two hundred twenty-one million, one hundred ten thousand, one hundred thirteen".