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211130000001 = 3261384571949
BaseRepresentation
bin1100010010100001010…
…1000010001010000001
3202011222000100021012200
43010220111002022001
511424343240000001
6240554120343413
721152666250414
oct3045025021201
9664860307180
10211130000001
11815a3420a08
1234b03014b69
1316ba91622ab
14a30c351b7b
15575a642086
hex3128542281

211130000001 has 12 divisors (see below), whose sum is σ = 309964991700. Its totient is φ = 138445901280.

The previous prime is 211129999981. The next prime is 211130000023. The reversal of 211130000001 is 100000031112.

It can be written as a sum of positive squares in 2 ways, for example, as 71717375601 + 139412624400 = 267801^2 + 373380^2 .

It is not a de Polignac number, because 211130000001 - 215 = 211129967233 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (211130000051) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 192285426 + ... + 192286523.

It is an arithmetic number, because the mean of its divisors is an integer number (25830415975).

Almost surely, 2211130000001 is an apocalyptic number.

It is an amenable number.

211130000001 is a deficient number, since it is larger than the sum of its proper divisors (98834991699).

211130000001 is a wasteful number, since it uses less digits than its factorization.

211130000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 384572016 (or 384572013 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 211130000001 its reverse (100000031112), we get a palindrome (311130031113).

The spelling of 211130000001 in words is "two hundred eleven billion, one hundred thirty million, one", and thus it is an aban number.

Divisors: 1 3 9 61 183 549 384571949 1153715847 3461147541 23458888889 70376666667 211130000001