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2033312022113 is a prime number
BaseRepresentation
bin11101100101101010110…
…101110011111001100001
321012101100000021220112212
4131211222311303321201
5231303210334201423
64154031325131505
7266621240010041
oct35455265637141
97171300256485
102033312022113
117143606a0079
1228a0a00b9b95
13119981b5a868
14705acb23721
1537d57781578
hex1d96ad73e61

2033312022113 has 2 divisors, whose sum is σ = 2033312022114. Its totient is φ = 2033312022112.

The previous prime is 2033312022103. The next prime is 2033312022139. The reversal of 2033312022113 is 3112202133302.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1235670122449 + 797641899664 = 1111607^2 + 893108^2 .

It is a cyclic number.

It is not a de Polignac number, because 2033312022113 - 24 = 2033312022097 is a prime.

It is not a weakly prime, because it can be changed into another prime (2033312022103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1016656011056 + 1016656011057.

It is an arithmetic number, because the mean of its divisors is an integer number (1016656011057).

Almost surely, 22033312022113 is an apocalyptic number.

It is an amenable number.

2033312022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2033312022113 is an equidigital number, since it uses as much as digits as its factorization.

2033312022113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2033312022113 its reverse (3112202133302), we get a palindrome (5145514155415).

The spelling of 2033312022113 in words is "two trillion, thirty-three billion, three hundred twelve million, twenty-two thousand, one hundred thirteen".