Base | Representation |
---|---|
bin | 11101100101101010110… |
… | …101110011111001100001 |
3 | 21012101100000021220112212 |
4 | 131211222311303321201 |
5 | 231303210334201423 |
6 | 4154031325131505 |
7 | 266621240010041 |
oct | 35455265637141 |
9 | 7171300256485 |
10 | 2033312022113 |
11 | 7143606a0079 |
12 | 28a0a00b9b95 |
13 | 119981b5a868 |
14 | 705acb23721 |
15 | 37d57781578 |
hex | 1d96ad73e61 |
2033312022113 has 2 divisors, whose sum is σ = 2033312022114. Its totient is φ = 2033312022112.
The previous prime is 2033312022103. The next prime is 2033312022139. The reversal of 2033312022113 is 3112202133302.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1235670122449 + 797641899664 = 1111607^2 + 893108^2 .
It is a cyclic number.
It is not a de Polignac number, because 2033312022113 - 24 = 2033312022097 is a prime.
It is not a weakly prime, because it can be changed into another prime (2033312022103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1016656011056 + 1016656011057.
It is an arithmetic number, because the mean of its divisors is an integer number (1016656011057).
Almost surely, 22033312022113 is an apocalyptic number.
It is an amenable number.
2033312022113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2033312022113 is an equidigital number, since it uses as much as digits as its factorization.
2033312022113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 2033312022113 its reverse (3112202133302), we get a palindrome (5145514155415).
The spelling of 2033312022113 in words is "two trillion, thirty-three billion, three hundred twelve million, twenty-two thousand, one hundred thirteen".
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