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20280433 is a prime number
BaseRepresentation
bin100110101011…
…1010001110001
31102011100112011
41031113101301
520142433213
62002402521
7334244425
oct115272161
942140464
1020280433
11104a1a98
126960441
134280c74
14299cb85
151ba903d
hex1357471

20280433 has 2 divisors, whose sum is σ = 20280434. Its totient is φ = 20280432.

The previous prime is 20280419. The next prime is 20280437. The reversal of 20280433 is 33408202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18722929 + 1557504 = 4327^2 + 1248^2 .

It is a cyclic number.

It is not a de Polignac number, because 20280433 - 25 = 20280401 is a prime.

It is a super-2 number, since 2×202804332 = 822591925334978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20280437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10140216 + 10140217.

It is an arithmetic number, because the mean of its divisors is an integer number (10140217).

Almost surely, 220280433 is an apocalyptic number.

It is an amenable number.

20280433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20280433 is an equidigital number, since it uses as much as digits as its factorization.

20280433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 20280433 is about 4503.3801749353. The cubic root of 20280433 is about 272.7045648535.

Adding to 20280433 its reverse (33408202), we get a palindrome (53688635).

The spelling of 20280433 in words is "twenty million, two hundred eighty thousand, four hundred thirty-three".