Base | Representation |
---|---|
bin | 101101110011000111000000… |
… | …011101011001101001010011 |
3 | 222102011222100111120122021001 |
4 | 231303013000131121221103 |
5 | 202400113441403310303 |
6 | 1552221014540242431 |
7 | 60266266115342650 |
oct | 5563070035315123 |
9 | 872158314518231 |
10 | 201424310213203 |
11 | 591a862aaa3630 |
12 | 1a711469b40417 |
13 | 885130052779c |
14 | 37a4dbab3ac27 |
15 | 184479656a31d |
hex | b731c0759a53 |
201424310213203 has 16 divisors (see below), whose sum is σ = 251127712053504. Its totient is φ = 156953195883360.
The previous prime is 201424310213171. The next prime is 201424310213213. The reversal of 201424310213203 is 302312013424102.
201424310213203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 201424310213203 - 25 = 201424310213171 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201424310213213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8431776 + ... + 21770242.
It is an arithmetic number, because the mean of its divisors is an integer number (15695482003344).
Almost surely, 2201424310213203 is an apocalyptic number.
201424310213203 is a deficient number, since it is larger than the sum of its proper divisors (49703401840301).
201424310213203 is a wasteful number, since it uses less digits than its factorization.
201424310213203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13534602.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 201424310213203 its reverse (302312013424102), we get a palindrome (503736323637305).
The spelling of 201424310213203 in words is "two hundred one trillion, four hundred twenty-four billion, three hundred ten million, two hundred thirteen thousand, two hundred three".
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