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201341023000 = 23531321637309
BaseRepresentation
bin1011101110000011011…
…1000011001100011000
3201020200210122201012221
42323200313003030120
511244321300214000
6232254512513424
720355263313025
oct2734067031430
9636623581187
10201341023000
117842a838677
123303084b874
1315ca90bb500
149a6024054c
15538606961a
hex2ee0dc3318

201341023000 has 192 divisors, whose sum is σ = 513367264800. Its totient is φ = 73875110400.

The previous prime is 201341022973. The next prime is 201341023001. The reversal of 201341023000 is 320143102.

It is a happy number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201341023001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 27543346 + ... + 27550654.

Almost surely, 2201341023000 is an apocalyptic number.

201341023000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201341023000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (256683632400).

201341023000 is an abundant number, since it is smaller than the sum of its proper divisors (312026241800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201341023000 is a wasteful number, since it uses less digits than its factorization.

201341023000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7519 (or 7492 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 201341023000 its reverse (320143102), we get a palindrome (201661166102).

The spelling of 201341023000 in words is "two hundred one billion, three hundred forty-one million, twenty-three thousand".