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20133311201 = 50867395803
BaseRepresentation
bin10010110000000010…
…011111001011100001
31220222010101011211122
4102300002133023201
5312213111424301
613125450422025
71311631215203
oct226002371341
956863334748
1020133311201
1185a1802773
123a9a731915
131b8b1b25c3
14d8dca8773
157cc80081b
hex4b009f2e1

20133311201 has 4 divisors (see below), whose sum is σ = 20133757872. Its totient is φ = 20132864532.

The previous prime is 20133311197. The next prime is 20133311203. The reversal of 20133311201 is 10211333102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20133311201 - 22 = 20133311197 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20133311201.

It is not an unprimeable number, because it can be changed into a prime (20133311203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147035 + ... + 248768.

It is an arithmetic number, because the mean of its divisors is an integer number (5033439468).

Almost surely, 220133311201 is an apocalyptic number.

It is an amenable number.

20133311201 is a deficient number, since it is larger than the sum of its proper divisors (446671).

20133311201 is an equidigital number, since it uses as much as digits as its factorization.

20133311201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446670.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 20133311201 its reverse (10211333102), we get a palindrome (30344644303).

The spelling of 20133311201 in words is "twenty billion, one hundred thirty-three million, three hundred eleven thousand, two hundred one".

Divisors: 1 50867 395803 20133311201