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201322310011211 is a prime number
BaseRepresentation
bin101101110001101000000000…
…110001100000100101001011
3222101211020001221012111201002
4231301220000301200211023
5202341431042330324321
61552102105322045215
760256025343051524
oct5561500061404513
9871736057174632
10201322310011211
11591693485a3134
121a6b574234980b
1388447c64cca8c
1437a00a21ab84b
151841cc692d20b
hexb71a00c6094b

201322310011211 has 2 divisors, whose sum is σ = 201322310011212. Its totient is φ = 201322310011210.

The previous prime is 201322310011183. The next prime is 201322310011223. The reversal of 201322310011211 is 112110013223102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201322310011211 is a prime.

It is not a weakly prime, because it can be changed into another prime (201322310061211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661155005605 + 100661155005606.

It is an arithmetic number, because the mean of its divisors is an integer number (100661155005606).

Almost surely, 2201322310011211 is an apocalyptic number.

201322310011211 is a deficient number, since it is larger than the sum of its proper divisors (1).

201322310011211 is an equidigital number, since it uses as much as digits as its factorization.

201322310011211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 201322310011211 its reverse (112110013223102), we get a palindrome (313432323234313).

The spelling of 201322310011211 in words is "two hundred one trillion, three hundred twenty-two billion, three hundred ten million, eleven thousand, two hundred eleven".