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200313131 is a prime number
BaseRepresentation
bin10111111000010…
…00100100101011
3111221220221221212
423330020210223
5402240010011
631513223335
74651430204
oct1374104453
9457827855
10200313131
11a3087247
1257101b4b
13326669a5
141c8645ab
15128bc08b
hexbf0892b

200313131 has 2 divisors, whose sum is σ = 200313132. Its totient is φ = 200313130.

The previous prime is 200313119. The next prime is 200313133. The reversal of 200313131 is 131313002.

200313131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200313131 - 210 = 200312107 is a prime.

It is a super-2 number, since 2×2003131312 = 80250700902046322, which contains 22 as substring.

Together with 200313133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (200313133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156565 + 100156566.

It is an arithmetic number, because the mean of its divisors is an integer number (100156566).

Almost surely, 2200313131 is an apocalyptic number.

200313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

200313131 is an equidigital number, since it uses as much as digits as its factorization.

200313131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 200313131 is about 14153.2021465109. The cubic root of 200313131 is about 585.1085887010.

Adding to 200313131 its reverse (131313002), we get a palindrome (331626133).

The spelling of 200313131 in words is "two hundred million, three hundred thirteen thousand, one hundred thirty-one".