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200120133 = 366706711
BaseRepresentation
bin10111110110110…
…01011101000101
3111221120011012210
423323121131011
5402212321013
631505134033
74646664423
oct1373313505
9457504183
10200120133
11a2a65244
125702a319
13325c9ba5
141c814113
151287ecc3
hexbed9745

200120133 has 4 divisors (see below), whose sum is σ = 266826848. Its totient is φ = 133413420.

The previous prime is 200120131. The next prime is 200120143. The reversal of 200120133 is 331021002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 200120133 - 21 = 200120131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200120131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33353353 + ... + 33353358.

It is an arithmetic number, because the mean of its divisors is an integer number (66706712).

Almost surely, 2200120133 is an apocalyptic number.

It is an amenable number.

200120133 is a deficient number, since it is larger than the sum of its proper divisors (66706715).

200120133 is an equidigital number, since it uses as much as digits as its factorization.

200120133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66706714.

The product of its (nonzero) digits is 36, while the sum is 12.

The square root of 200120133 is about 14146.3823290621. The cubic root of 200120133 is about 584.9206145474.

Adding to 200120133 its reverse (331021002), we get a palindrome (531141135).

The spelling of 200120133 in words is "two hundred million, one hundred twenty thousand, one hundred thirty-three".

Divisors: 1 3 66706711 200120133