Base | Representation |
---|---|
bin | 111011101000110… |
… | …1011101011000001 |
3 | 12011110110122002221 |
4 | 1313101223223001 |
5 | 13044241432113 |
6 | 530323011041 |
7 | 100406162566 |
oct | 16721535301 |
9 | 5143418087 |
10 | 2001124033 |
11 | 937645117 |
12 | 47a209a81 |
13 | 25b77bb7c |
14 | 14daac86d |
15 | baa3598d |
hex | 7746bac1 |
2001124033 has 4 divisors (see below), whose sum is σ = 2070128340. Its totient is φ = 1932119728.
The previous prime is 2001124003. The next prime is 2001124109. The reversal of 2001124033 is 3304211002.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1704698944 + 296425089 = 41288^2 + 17217^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001124033 - 25 = 2001124001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2001123998 and 2001124016.
It is not an unprimeable number, because it can be changed into a prime (2001124003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34502110 + ... + 34502167.
It is an arithmetic number, because the mean of its divisors is an integer number (517532085).
Almost surely, 22001124033 is an apocalyptic number.
It is an amenable number.
2001124033 is a deficient number, since it is larger than the sum of its proper divisors (69004307).
2001124033 is an equidigital number, since it uses as much as digits as its factorization.
2001124033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69004306.
The product of its (nonzero) digits is 144, while the sum is 16.
The square root of 2001124033 is about 44733.9248557513. The cubic root of 2001124033 is about 1260.1570378303.
Adding to 2001124033 its reverse (3304211002), we get a palindrome (5305335035).
It can be divided in two parts, 20011 and 24033, that added together give a palindrome (44044).
The spelling of 2001124033 in words is "two billion, one million, one hundred twenty-four thousand, thirty-three".
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