200112201101 has 2 divisors, whose sum is σ = 200112201102. Its totient is φ = 200112201100.

The previous prime is 200112201089. The next prime is 200112201103. The reversal of 200112201101 is 101102211002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 198471141001 + 1641060100 = 445501^2 + 40510^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200112201101 is a prime.

It is a super-2 number, since 2×200112201101² (a number of 23 digits) contains 22 as substring.

Together with 200112201103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200112201103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056100550 + 100056100551.

It is an arithmetic number, because the mean of its divisors is an integer number (100056100551).

Almost surely, 2^200112201101 is an apocalyptic number.

It is an amenable number.

200112201101 is a deficient number, since it is larger than the sum of its proper divisors (1).

200112201101 is an equidigital number, since it uses as much as digits as its factorization.

200112201101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 200112201101 its reverse (101102211002), we get a palindrome (301214412103).

Subtracting from 200112201101 its reverse (101102211002), we obtain a palindrome (99009990099).

The spelling of 200112201101 in words is "two hundred billion, one hundred twelve million, two hundred one thousand, one hundred one".