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20004013500 = 2235325795171
BaseRepresentation
bin10010101000010101…
…010000010110111100
31220122010002011201220
4102220111100112330
5311432011413000
613104551233340
71305501211032
oct225025202674
956563064656
1020004013500
118535820469
123a63378850
131b6a4816a3
14d7aa4c552
157c12b01a0
hex4a85505bc

20004013500 has 96 divisors (see below), whose sum is σ = 58285543680. Its totient is φ = 5331304000.

The previous prime is 20004013493. The next prime is 20004013507. The reversal of 20004013500 is 531040002.

It is an interprime number because it is at equal distance from previous prime (20004013493) and next prime (20004013507).

It is a super-2 number, since 2×200040135002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 20004013500.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20004013507) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3865915 + ... + 3871085.

It is an arithmetic number, because the mean of its divisors is an integer number (607141080).

Almost surely, 220004013500 is an apocalyptic number.

20004013500 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20004013500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29142771840).

20004013500 is an abundant number, since it is smaller than the sum of its proper divisors (38281530180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20004013500 is a wasteful number, since it uses less digits than its factorization.

20004013500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7772 (or 7760 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 15.

Adding to 20004013500 its reverse (531040002), we get a palindrome (20535053502).

The spelling of 20004013500 in words is "twenty billion, four million, thirteen thousand, five hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 125 150 250 300 375 500 750 1500 2579 5158 5171 7737 10316 10342 12895 15474 15513 20684 25790 25855 30948 31026 38685 51580 51710 62052 64475 77370 77565 103420 128950 129275 154740 155130 193425 257900 258550 310260 322375 386850 387825 517100 644750 646375 773700 775650 967125 1289500 1292750 1551300 1934250 1939125 2585500 3868500 3878250 7756500 13336009 26672018 40008027 53344036 66680045 80016054 133360090 160032108 200040135 266720180 333400225 400080270 666800450 800160540 1000200675 1333600900 1667001125 2000401350 3334002250 4000802700 5001003375 6668004500 10002006750 20004013500