19814 has 4 divisors (see below), whose sum is σ = 29724. Its totient is φ = 9906.

The previous prime is 19813. The next prime is 19819. The reversal of 19814 is 41891.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41891 = 163 ⋅257.

It is a super-3 number, since 3×19814³ = 23336607975432, which contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 19814.

It is a congruent number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 19814.

It is not an unprimeable number, because it can be changed into a prime (19813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4952 + ... + 4955.

It is an arithmetic number, because the mean of its divisors is an integer number (7431).

2¹⁹⁸¹⁴ is an apocalyptic number.

19814 is a deficient number, since it is larger than the sum of its proper divisors (9910).

19814 is an equidigital number, since it uses as much as digits as its factorization.

19814 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9909.

The product of its digits is 288, while the sum is 23.

The square root of 19814 is about 140.7622108380. The cubic root of 19814 is about 27.0597670081.

Subtracting from 19814 its sum of digits (23), we obtain a palindrome (19791).

Adding to 19814 its product of digits (288), we get a palindrome (20102).

It can be divided in two parts, 198 and 14, that multiplied together give a palindrome (2772).

The spelling of 19814 in words is "nineteen thousand, eight hundred fourteen".