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198135 = 32571737
BaseRepresentation
bin110000010111110111
3101001210100
4300113313
522320020
64125143
71453440
oct602767
9331710
10198135
11125953
12967b3
136c252
14522c7
153da90
hex305f7

198135 has 48 divisors (see below), whose sum is σ = 426816. Its totient is φ = 82944.

The previous prime is 198127. The next prime is 198139. The reversal of 198135 is 531891.

198135 is a nontrivial binomial coefficient, being equal to C(630, 2).

It is not a de Polignac number, because 198135 - 23 = 198127 is a prime.

It is a super-3 number, since 3×1981353 = 23334841344331125, which contains 333 as substring.

It is an Ulam number.

Its product of digits (1080) is a multiple of the sum of its prime factors (72).

It is a junction number, because it is equal to n+sod(n) for n = 198099 and 198108.

It is a congruent number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 198135.

It is not an unprimeable number, because it can be changed into a prime (198139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5337 + ... + 5373.

It is an arithmetic number, because the mean of its divisors is an integer number (8892).

2198135 is an apocalyptic number.

198135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

198135 is the 629-th triangular number and also the 315-th hexagonal number.

198135 is an abundant number, since it is smaller than the sum of its proper divisors (228681).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

198135 is a wasteful number, since it uses less digits than its factorization.

198135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72 (or 69 counting only the distinct ones).

The product of its digits is 1080, while the sum is 27.

The square root of 198135 is about 445.1235783465. The cubic root of 198135 is about 58.2980103610.

It can be divided in two parts, 1981 and 35, that added together give a triangular number (2016 = T63).

The spelling of 198135 in words is "one hundred ninety-eight thousand, one hundred thirty-five".

Divisors: 1 3 5 7 9 15 17 21 35 37 45 51 63 85 105 111 119 153 185 255 259 315 333 357 555 595 629 765 777 1071 1295 1665 1785 1887 2331 3145 3885 4403 5355 5661 9435 11655 13209 22015 28305 39627 66045 198135