Base | Representation |
---|---|
bin | 1000111110001110101… |
… | …0110101101000011111 |
3 | 112201212112012210022102 |
4 | 2033203222311220133 |
5 | 10011141214404434 |
6 | 154451302235315 |
7 | 14064551146301 |
oct | 2174352655037 |
9 | 481775183272 |
10 | 154143513119 |
11 | 5a40aaa3962 |
12 | 25a5a425b3b |
13 | 116c6b3b27b |
14 | 7663bc1971 |
15 | 402275207e |
hex | 23e3ab5a1f |
154143513119 has 2 divisors, whose sum is σ = 154143513120. Its totient is φ = 154143513118.
The previous prime is 154143513113. The next prime is 154143513127. The reversal of 154143513119 is 911315341451.
It is a weak prime.
It is an emirp because it is prime and its reverse (911315341451) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-154143513119 is a prime.
It is a super-2 number, since 2×1541435131192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (154143513113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77071756559 + 77071756560.
It is an arithmetic number, because the mean of its divisors is an integer number (77071756560).
Almost surely, 2154143513119 is an apocalyptic number.
154143513119 is a deficient number, since it is larger than the sum of its proper divisors (1).
154143513119 is an equidigital number, since it uses as much as digits as its factorization.
154143513119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 32400, while the sum is 38.
The spelling of 154143513119 in words is "one hundred fifty-four billion, one hundred forty-three million, five hundred thirteen thousand, one hundred nineteen".
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