1530014100113 has 4 divisors (see below), whose sum is σ = 1542061455360. Its totient is φ = 1517966744868.

The previous prime is 1530014100107. The next prime is 1530014100127. The reversal of 1530014100113 is 3110014100351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1530014100113 is a prime.

It is a super-2 number, since 2×1530014100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1530014100313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6023677433 + ... + 6023677686.

It is an arithmetic number, because the mean of its divisors is an integer number (385515363840).

Almost surely, 2^{1530014100113} is an apocalyptic number.

It is an amenable number.

1530014100113 is a deficient number, since it is larger than the sum of its proper divisors (12047355247).

1530014100113 is a wasteful number, since it uses less digits than its factorization.

1530014100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12047355246.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 1530014100113 its reverse (3110014100351), we get a palindrome (4640028200464).

The spelling of 1530014100113 in words is "one trillion, five hundred thirty billion, fourteen million, one hundred thousand, one hundred thirteen".