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152145537 = 350715179
BaseRepresentation
bin10010001000110…
…00111010000001
3101121021210102220
421010120322001
5302422124122
623033001253
73525133665
oct1104307201
9347253386
10152145537
1178978215
1242b53229
13256a065b
14162c68a5
15d55525c
hex9118e81

152145537 has 4 divisors (see below), whose sum is σ = 202860720. Its totient is φ = 101430356.

The previous prime is 152145527. The next prime is 152145569. The reversal of 152145537 is 735541251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152145537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 152145498 and 152145507.

It is not an unprimeable number, because it can be changed into a prime (152145527) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25357587 + ... + 25357592.

It is an arithmetic number, because the mean of its divisors is an integer number (50715180).

Almost surely, 2152145537 is an apocalyptic number.

It is an amenable number.

152145537 is a deficient number, since it is larger than the sum of its proper divisors (50715183).

152145537 is an equidigital number, since it uses as much as digits as its factorization.

152145537 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50715182.

The product of its digits is 21000, while the sum is 33.

The square root of 152145537 is about 12334.7288985206. The cubic root of 152145537 is about 533.8506048718.

Adding to 152145537 its reverse (735541251), we get a palindrome (887686788).

The spelling of 152145537 in words is "one hundred fifty-two million, one hundred forty-five thousand, five hundred thirty-seven".

Divisors: 1 3 50715179 152145537