Search a number
-
+
1512012313211 is a prime number
BaseRepresentation
bin10110000000001010111…
…101001111001001111011
312100112202201220212121212
4112000022331033021323
5144233100123010321
63114335303153335
7214145034414611
oct26001275171173
95315681825555
101512012313211
11533271595074
12205055a4584b
13ac774c9c84a
1453278b716b1
15294e6c4d55b
hex1600af4f27b

1512012313211 has 2 divisors, whose sum is σ = 1512012313212. Its totient is φ = 1512012313210.

The previous prime is 1512012313171. The next prime is 1512012313213. The reversal of 1512012313211 is 1123132102151.

It is a strong prime.

It is an emirp because it is prime and its reverse (1123132102151) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1512012313211 is a prime.

It is a Sophie Germain prime.

Together with 1512012313213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1512012313213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 756006156605 + 756006156606.

It is an arithmetic number, because the mean of its divisors is an integer number (756006156606).

Almost surely, 21512012313211 is an apocalyptic number.

1512012313211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1512012313211 is an equidigital number, since it uses as much as digits as its factorization.

1512012313211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 1512012313211 its reverse (1123132102151), we get a palindrome (2635144415362).

The spelling of 1512012313211 in words is "one trillion, five hundred twelve billion, twelve million, three hundred thirteen thousand, two hundred eleven".