Base | Representation |
---|---|
bin | 100010010111001000101010… |
… | …101000001010110010000111 |
3 | 201211002020222222120222011221 |
4 | 202113020222220022302013 |
5 | 124302001243204400210 |
6 | 1253225051455141211 |
7 | 43555210405053634 |
oct | 4227105250126207 |
9 | 654066888528157 |
10 | 151123434450055 |
11 | 441750a7a70451 |
12 | 14b48898514807 |
13 | 6642b56717282 |
14 | 29465add8318b |
15 | 127110240b1da |
hex | 89722aa0ac87 |
151123434450055 has 8 divisors (see below), whose sum is σ = 181348376704272. Its totient is φ = 120898577317248.
The previous prime is 151123434449971. The next prime is 151123434450067. The reversal of 151123434450055 is 550054434321151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 151123434450055 - 239 = 150573678636167 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151123434449993 and 151123434450020.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17307057 + ... + 24531226.
It is an arithmetic number, because the mean of its divisors is an integer number (22668547088034).
Almost surely, 2151123434450055 is an apocalyptic number.
151123434450055 is a deficient number, since it is larger than the sum of its proper divisors (30224942254217).
151123434450055 is an equidigital number, since it uses as much as digits as its factorization.
151123434450055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42560705.
The product of its (nonzero) digits is 720000, while the sum is 43.
The spelling of 151123434450055 in words is "one hundred fifty-one trillion, one hundred twenty-three billion, four hundred thirty-four million, four hundred fifty thousand, fifty-five".
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