Search a number
-
+
149403 = 349801
BaseRepresentation
bin100100011110011011
321120221110
4210132123
514240103
63111403
71161402
oct443633
9246843
10149403
11a2281
1272563
1353007
143c639
152e403
hex2479b

149403 has 4 divisors (see below), whose sum is σ = 199208. Its totient is φ = 99600.

The previous prime is 149399. The next prime is 149411. The reversal of 149403 is 304941.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 149403 - 22 = 149399 is a prime.

It is a D-number.

It is a Duffinian number.

It is a plaindrome in base 16.

It is a self number, because there is not a number n which added to its sum of digits gives 149403.

It is not an unprimeable number, because it can be changed into a prime (149423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24898 + ... + 24903.

It is an arithmetic number, because the mean of its divisors is an integer number (49802).

2149403 is an apocalyptic number.

149403 is a deficient number, since it is larger than the sum of its proper divisors (49805).

149403 is an equidigital number, since it uses as much as digits as its factorization.

149403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49804.

The product of its (nonzero) digits is 432, while the sum is 21.

The square root of 149403 is about 386.5268425349. The cubic root of 149403 is about 53.0623450504.

The spelling of 149403 in words is "one hundred forty-nine thousand, four hundred three".

Divisors: 1 3 49801 149403