Base | Representation |
---|---|
bin | 10101100011101000000… |
… | …000001010001001111111 |
3 | 12020121122121021012020221 |
4 | 111203220000022021333 |
5 | 143232311420334120 |
6 | 3052310005322211 |
7 | 212011336432243 |
oct | 25435000121177 |
9 | 5217577235227 |
10 | 1481361105535 |
11 | 5212727a8083 |
12 | 1bb120a06367 |
13 | a98cba1cb7c |
14 | 519ac050423 |
15 | 28800d8e0aa |
hex | 158e800a27f |
1481361105535 has 4 divisors (see below), whose sum is σ = 1777633326648. Its totient is φ = 1185088884424.
The previous prime is 1481361105527. The next prime is 1481361105541. The reversal of 1481361105535 is 5355011631841.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1481361105535 - 23 = 1481361105527 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1481361105491 and 1481361105500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148136110549 + ... + 148136110558.
It is an arithmetic number, because the mean of its divisors is an integer number (444408331662).
Almost surely, 21481361105535 is an apocalyptic number.
1481361105535 is a deficient number, since it is larger than the sum of its proper divisors (296272221113).
1481361105535 is an equidigital number, since it uses as much as digits as its factorization.
1481361105535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 296272221112.
The product of its (nonzero) digits is 216000, while the sum is 43.
The spelling of 1481361105535 in words is "one trillion, four hundred eighty-one billion, three hundred sixty-one million, one hundred five thousand, five hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •