Base | Representation |
---|---|
bin | 11011000110100010… |
… | …01100110010100111 |
3 | 1101120001001121212011 |
4 | 31203101030302213 |
5 | 214244342330421 |
6 | 10403452335051 |
7 | 1023366656245 |
oct | 154321146247 |
9 | 41501047764 |
10 | 14550355111 |
11 | 6197329176 |
12 | 29a0a74487 |
13 | 14ab644ba6 |
14 | 9c0619795 |
15 | 5a25e64e1 |
hex | 36344cca7 |
14550355111 has 2 divisors, whose sum is σ = 14550355112. Its totient is φ = 14550355110.
The previous prime is 14550355091. The next prime is 14550355153. The reversal of 14550355111 is 11155305541.
It is a happy number.
14550355111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (11155305541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14550355111 - 221 = 14548257959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14550355511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7275177555 + 7275177556.
It is an arithmetic number, because the mean of its divisors is an integer number (7275177556).
Almost surely, 214550355111 is an apocalyptic number.
14550355111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14550355111 is an equidigital number, since it uses as much as digits as its factorization.
14550355111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 14550355111 in words is "fourteen billion, five hundred fifty million, three hundred fifty-five thousand, one hundred eleven".
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