1454442047 has 2 divisors, whose sum is σ = 1454442048. Its totient is φ = 1454442046.

The previous prime is 1454442023. The next prime is 1454442049. The reversal of 1454442047 is 7402444541.

It is a strong prime.

It is an emirp because it is prime and its reverse (7402444541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1454442047 - 2¹² = 1454437951 is a prime.

It is a super-3 number, since 3×1454442047³ (a number of 28 digits) contains 333 as substring.

Together with 1454442049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1454441998 and 1454442016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1454442049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727221023 + 727221024.

It is an arithmetic number, because the mean of its divisors is an integer number (727221024).

Almost surely, 2^1454442047 is an apocalyptic number.

1454442047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1454442047 is an equidigital number, since it uses as much as digits as its factorization.

1454442047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 71680, while the sum is 35.

The square root of 1454442047 is about 38137.1478613700. The cubic root of 1454442047 is about 1133.0058191366.

Adding to 1454442047 its reverse (7402444541), we get a palindrome (8856886588).

The spelling of 1454442047 in words is "one billion, four hundred fifty-four million, four hundred forty-two thousand, forty-seven".