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145403 = 971499
BaseRepresentation
bin100011011111111011
321101110022
4203133323
514123103
63041055
71143626
oct433773
9241408
10145403
119a275
127018b
135124b
143adbd
152d138
hex237fb

145403 has 4 divisors (see below), whose sum is σ = 147000. Its totient is φ = 143808.

The previous prime is 145399. The next prime is 145417. The reversal of 145403 is 304541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145403 - 22 = 145399 is a prime.

It is a super-2 number, since 2×1454032 = 42284064818, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 145403.

It is not an unprimeable number, because it can be changed into a prime (145423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 653 + ... + 846.

It is an arithmetic number, because the mean of its divisors is an integer number (36750).

2145403 is an apocalyptic number.

145403 is a deficient number, since it is larger than the sum of its proper divisors (1597).

145403 is an equidigital number, since it uses as much as digits as its factorization.

145403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1596.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 145403 is about 381.3174530493. The cubic root of 145403 is about 52.5845048741.

Adding to 145403 its reverse (304541), we get a palindrome (449944).

The spelling of 145403 in words is "one hundred forty-five thousand, four hundred three".

Divisors: 1 97 1499 145403