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14534222413 is a prime number
BaseRepresentation
bin11011000100100111…
…01010001001001101
31101111220200222221211
431202103222021031
5214231230104123
610402114454421
71023112565164
oct154223521115
941456628854
1014534222413
11618920a467
122997594411
1314a81b6b09
149bc41a3db
155a0eab40d
hex3624ea24d

14534222413 has 2 divisors, whose sum is σ = 14534222414. Its totient is φ = 14534222412.

The previous prime is 14534222411. The next prime is 14534222419. The reversal of 14534222413 is 31422243541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14438906244 + 95316169 = 120162^2 + 9763^2 .

It is a cyclic number.

It is not a de Polignac number, because 14534222413 - 21 = 14534222411 is a prime.

It is a super-2 number, since 2×145342224132 (a number of 21 digits) contains 22 as substring.

Together with 14534222411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14534222411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267111206 + 7267111207.

It is an arithmetic number, because the mean of its divisors is an integer number (7267111207).

Almost surely, 214534222413 is an apocalyptic number.

It is an amenable number.

14534222413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14534222413 is an equidigital number, since it uses as much as digits as its factorization.

14534222413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 23040, while the sum is 31.

Adding to 14534222413 its reverse (31422243541), we get a palindrome (45956465954).

The spelling of 14534222413 in words is "fourteen billion, five hundred thirty-four million, two hundred twenty-two thousand, four hundred thirteen".