14525403133 has 4 divisors (see below), whose sum is σ = 14525676928. Its totient is φ = 14525129340.

The previous prime is 14525403127. The next prime is 14525403161. The reversal of 14525403133 is 33130452541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14525403133 - 2¹³ = 14525394941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14525403095 and 14525403104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14525407133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28941 + ... + 172882.

It is an arithmetic number, because the mean of its divisors is an integer number (3631419232).

Almost surely, 2^14525403133 is an apocalyptic number.

It is an amenable number.

14525403133 is a deficient number, since it is larger than the sum of its proper divisors (273795).

14525403133 is an equidigital number, since it uses as much as digits as its factorization.

14525403133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 273794.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 14525403133 its reverse (33130452541), we get a palindrome (47655855674).

The spelling of 14525403133 in words is "fourteen billion, five hundred twenty-five million, four hundred three thousand, one hundred thirty-three".