1450250105401 has 2 divisors, whose sum is σ = 1450250105402. Its totient is φ = 1450250105400.

The previous prime is 1450250105389. The next prime is 1450250105429. The reversal of 1450250105401 is 1045010520541.

It is an a-pointer prime, because the next prime (1450250105429) can be obtained adding 1450250105401 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1399004012025 + 51246093376 = 1182795^2 + 226376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1450250105401 is a prime.

It is a super-2 number, since 2×1450250105401² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1450250105401.

It is not a weakly prime, because it can be changed into another prime (1450250100401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725125052700 + 725125052701.

It is an arithmetic number, because the mean of its divisors is an integer number (725125052701).

Almost surely, 2^{1450250105401} is an apocalyptic number.

It is an amenable number.

1450250105401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1450250105401 is an equidigital number, since it uses as much as digits as its factorization.

1450250105401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4000, while the sum is 28.

Adding to 1450250105401 its reverse (1045010520541), we get a palindrome (2495260625942).

The spelling of 1450250105401 in words is "one trillion, four hundred fifty billion, two hundred fifty million, one hundred five thousand, four hundred one".