Base | Representation |
---|---|
bin | 1101001001001011010100… |
… | …1110011011100111111001 |
3 | 1220011112100200010220020011 |
4 | 3102102311032123213321 |
5 | 3343232240433134001 |
6 | 50422501304101521 |
7 | 3021033642000625 |
oct | 322226516334771 |
9 | 56145320126204 |
10 | 14451310443001 |
11 | 4671848000283 |
12 | 17549167648a1 |
13 | 80a9a2985363 |
14 | 37d639000185 |
15 | 1a0da2240d51 |
hex | d24b539b9f9 |
14451310443001 has 4 divisors (see below), whose sum is σ = 14456488271104. Its totient is φ = 14446132614900.
The previous prime is 14451310442999. The next prime is 14451310443007. The reversal of 14451310443001 is 10034401315441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14451310443001 - 21 = 14451310442999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14451310443007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2588909865 + ... + 2588915446.
It is an arithmetic number, because the mean of its divisors is an integer number (3614122067776).
Almost surely, 214451310443001 is an apocalyptic number.
It is an amenable number.
14451310443001 is a deficient number, since it is larger than the sum of its proper divisors (5177828103).
14451310443001 is an equidigital number, since it uses as much as digits as its factorization.
14451310443001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5177828102.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 14451310443001 its reverse (10034401315441), we get a palindrome (24485711758442).
The spelling of 14451310443001 in words is "fourteen trillion, four hundred fifty-one billion, three hundred ten million, four hundred forty-three thousand, one".
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