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14430000121 is a prime number
BaseRepresentation
bin11010111000001100…
…00101001111111001
31101020122120221211221
431130012011033321
5214023040000441
610343512552041
71020405656125
oct153406051771
941218527757
1014430000121
1161353a4739
1229686b2621
13148c725514
149ac64a585
15596c708d1
hex35c1853f9

14430000121 has 2 divisors, whose sum is σ = 14430000122. Its totient is φ = 14430000120.

The previous prime is 14430000103. The next prime is 14430000161. The reversal of 14430000121 is 12100003441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7985924496 + 6444075625 = 89364^2 + 80275^2 .

It is a cyclic number.

It is not a de Polignac number, because 14430000121 - 25 = 14430000089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14430000095 and 14430000104.

It is not a weakly prime, because it can be changed into another prime (14430000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7215000060 + 7215000061.

It is an arithmetic number, because the mean of its divisors is an integer number (7215000061).

Almost surely, 214430000121 is an apocalyptic number.

It is an amenable number.

14430000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14430000121 is an equidigital number, since it uses as much as digits as its factorization.

14430000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 14430000121 its reverse (12100003441), we get a palindrome (26530003562).

The spelling of 14430000121 in words is "fourteen billion, four hundred thirty million, one hundred twenty-one", and thus it is an aban number.