Base | Representation |
---|---|
bin | 1000010110010100111… |
… | …0011011010001011111 |
3 | 111201020000222202211021 |
4 | 2011211032123101133 |
5 | 4322222120420221 |
6 | 145520345505011 |
7 | 13235245411060 |
oct | 2054516332137 |
9 | 451200882737 |
10 | 143432201311 |
11 | 55913813853 |
12 | 2396b1a2167 |
13 | 106aa980a49 |
14 | 6d293bc567 |
15 | 3ae71da041 |
hex | 216539b45f |
143432201311 has 4 divisors (see below), whose sum is σ = 163922515792. Its totient is φ = 122941886832.
The previous prime is 143432201267. The next prime is 143432201359. The reversal of 143432201311 is 113102234341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113102234341 = 11173 ⋅10122817.
It is a cyclic number.
It is not a de Polignac number, because 143432201311 - 213 = 143432193119 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143432201611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10245157230 + ... + 10245157243.
It is an arithmetic number, because the mean of its divisors is an integer number (40980628948).
Almost surely, 2143432201311 is an apocalyptic number.
143432201311 is a deficient number, since it is larger than the sum of its proper divisors (20490314481).
143432201311 is an equidigital number, since it uses as much as digits as its factorization.
143432201311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20490314480.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 143432201311 its reverse (113102234341), we get a palindrome (256534435652).
The spelling of 143432201311 in words is "one hundred forty-three billion, four hundred thirty-two million, two hundred one thousand, three hundred eleven".
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