Base | Representation |
---|---|
bin | 1000010110010000101… |
… | …0101001000100001011 |
3 | 111201011210112222221001 |
4 | 2011210022221010023 |
5 | 4322203043311021 |
6 | 145514512555431 |
7 | 13234641362404 |
oct | 2054412510413 |
9 | 451153488831 |
10 | 143414432011 |
11 | 55904787484 |
12 | 23965252b77 |
13 | 106a709ba76 |
14 | 6d26cb49ab |
15 | 3ae587a091 |
hex | 21642a910b |
143414432011 has 2 divisors, whose sum is σ = 143414432012. Its totient is φ = 143414432010.
The previous prime is 143414431999. The next prime is 143414432017. The reversal of 143414432011 is 110234414341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143414432011 - 213 = 143414423819 is a prime.
It is not a weakly prime, because it can be changed into another prime (143414432017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71707216005 + 71707216006.
It is an arithmetic number, because the mean of its divisors is an integer number (71707216006).
Almost surely, 2143414432011 is an apocalyptic number.
143414432011 is a deficient number, since it is larger than the sum of its proper divisors (1).
143414432011 is an equidigital number, since it uses as much as digits as its factorization.
143414432011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 143414432011 its reverse (110234414341), we get a palindrome (253648846352).
The spelling of 143414432011 in words is "one hundred forty-three billion, four hundred fourteen million, four hundred thirty-two thousand, eleven".
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